The perimeter of triangle is 38 cm, AB=AC and L(AB)=AC and L (AB) greater than L( BC) by 7 cm. find the length of sides of triangle ABC.
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Answer:14.6, 14.6 ,22.4
Step-by-step explanation:It is given that l (AB)=l (AC) and l (AB)=l (BC)+7
and the length of the perimeter is 38 cm
Now,
L (AB)+L (AC)+L (BC)= 37
L (AB)+ L (AB) + L(AB)-7=37
3×L (AB)=44
L (AB)=44÷3
L (AB)=L (AC)=14.6
L (BC)=22.4
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