Question

the perimeter of triangle is 6a^2-4a+9 and two of its side's are a^2-2a+1 and 3a^2-5p+3
find the third side

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Answer 1

Step-by-step explanation:

6a^2-4a+9=a^2-2a+1+3a^2-5p+3

= 5a^2-7a+4 + X

6a^2-5a^2-4a+7a+9-4 = X

X = a^2+3a+5

So

a^2+3a+5 will be the 3rd side of Triangle

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Answer 2

Answer:

I think it's 2a²+3a+5

Step-by-step explanation:

if we add a²-2a+1+3a²-5a+3

we get 4a²-7a+4

and if we subtract 6a²-4a+9-4a² +7a-4

we get 2a²+3a+5