Question

the perimeter of triangle is x^(2)y +10 units one of the side is length x^2y-4 units and another side is 3-2x^2y units find length of third side

Answer 1

Answer:

thanks for the free points and please mark as brainliest

Answer 2

Answer:

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Given, one point =(2,−3)

Let, other point =(10,b)

absicca is x cordinate

∴

(10−2)

2

+(b+3)

2

=10

8

2

+(b

2

+9+6b)

=10

Squaring both the sides, we get

64+b

2

+9+6b=100

(b+3)

2

=36

∴ b+3=6 and b+3=−6

∴ b=3 and b=−9