Question

The perimeter of triangle with vertices (0,4),(0,0) and (3,0)is​

Answer 1

Answer:

12 units

Step-by-step explanation:

The vertices of the triangle are A(0,4), B(0,0) & C(3,0).

Using distance formula, $\sqrt{[x_{1} - x_{2}]^{2} + [y_{1} - y_{2}]^{2}}$

AB = 4 units

BC = 3 units

AC = 5 units

So, the perimeter of the triangle = AB + BC + CA = 3 + 4 + 5 = 12 units

Hope this helps.....

Answer 2

Given:-

• Vertices of triangle is (0, 4),(0,0) and (3,0).

To find:-

• Perimeter of triangle.

$\sf\blue{SolutioN:-}$

• For perimeter we need to find 3 side of triangle.
• The figure forms after marking points is of right angle triangle.

For third side...

Formula used:-

Pythagoras theorem:-

✣ (Base)² + (Perpendicular)² = (Hypotenuse)²

• AB = 4 units and BC = 3 units

$\implies \sf {(3)}^{2} = {(4)}^{2} = {(</strong><strong>AC</strong><strong>)}^{2} \\ \implies \sf9 + 1</strong><strong>6</strong><strong> = {(</strong><strong>AC</strong><strong>)}^{2} \\ \implies \sf2</strong><strong>5</strong><strong> = {</strong><strong>(</strong><strong>AC</strong><strong>)}^{2} \\ \impl</strong><strong>i</strong><strong>es \sf \sqrt{2</strong><strong>5</strong><strong>} = </strong><strong>AC</strong><strong>\\ \implies \sf \: </strong><strong>AC</strong><strong> </strong><strong>=</strong><strong> </strong><strong>5</strong><strong> </strong><strong>$

So, AC = 5 units.

We know that,

Perimeter of triangle = A + B + C

In which A , B and C are sides of triangle.

So, Put values in formula

⇒4 + 5 + 3

⇒12 units.

Therefore, Perimeter is 12 units.