Question

the perimeter of triangle withe verticies of(0, 4)(0, 0) and(3, 0)​

Answer 1

Let ABC be a triangle having

A(0,4);B(0,0);C(3,0)

Using distance formula, we get

$\small{AB= \sqrt{(0 - 0) {}^{2} +( 0 - 4) {}^{2} } = \sqrt{16} = 4}$

$\small{BC= \sqrt{(3 - 0) {}^{2} + (0 + 0) {}^{2} } = \sqrt{9} = 3}$

$\small{CA= \sqrt{(0 - 3) {}^{2} + (4 - 0) {}^{2} } = \sqrt{25} = 5}$

Perimeter of △ABC=AB+BC+CA=4+3+5=12