Question

The perimeter of triangular field is 240m. Its two sides are 78m and 50m. Find the area of triangular field and the length of

the altitude on the side of 50m length from its opposite vertex.​

Answer 1

we don't need the information of the opposite vertices

of we know the 2 sides n perimeter of the traingle

we can easily find the area and the third side os triangle like so..

area of traingle - 1/2 *base*height

=1/2*78*50

area of traingle= 1950m^2

Answer 2

Given:-

• Perimeter of triangle field = 240m.
• Length of the two sides = 78m and 50m.

To find:-

• Find the area of trianglular field.?

Solutions:-

• Perimeter of trianglular field = 240m.

• Let the third sides be x.

=> 240 = 78 + 50 + x

=> 240 = 128 + x

=> 240 - 128 = x

=> x = 112

So, the third side is 112m

Area of triangle be heroe's formula;

Therefore,

√s(s - a)(s - b)(s - c)

• s = (a + b + c)/2

• a = 50
• b = 78
• c = 112

=> s = (50 + 78 + 112)/2

=> s = 240/2

=> s = 120

Area of trianglular field;

=> √120(120 - 50)(120 - 78)(120 - 112)

=> √120 × 70 × 42 × 8

=> √28,22,400

=> 1680m²

Area of the => 1/2 × base × height

• Let the height be h m.

Area of triangle => 1/2 × 50 × h

=> 1680 = 1/2 × 50 × h

=> 1680 = 25 × h

=> h = 1680/25

=> h = 67.2

Hence, the length of altitude is 67.2m.