Math, asked by vivekreddy61890, 9 months ago

The perimeter of triangular field is 270 metre
and it's sides are in the ratio 25 : 17 : 12. Find its area .

Answers

Answered by surbhivihar
1

Step-by-step explanation:

perimeter is the sum of all sides

let side will be X.( 25x) (17x) (12x)

so, 25x+17x+12x = 270

54x = 270

X = 5

the three side will be

25x = 25*5 = 125

17x = 17*5 = 85

12x = 12*5 = 60.....

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Answered by chauhanbunty635
0

Answer:

perimeter of triangle = sum of sides

so let sides be a= 25x , b= 17x c= 12x

25x + 17x + 12x = 270

54x = 270

x= 5

now the actual sides are , a= 25 x 5 = 125 m

b= 17 x 5 = 85 m

c= 12 x 5 = 60 m

now we find semiperimeter ( S) i. e 270/2 = 135 m

area of triangle ,by heron's formula = ✓S( S-a) (S-b) (S-c)

= ✓135( 135-125) (135-85) (135-60)

= ✓135( 10 ) (50) (75)

= √3x45x 5x2x5x5x2x5x5x3

= √ 3x3x3x5x5x2x5x5x2x5x5x3

= 5x5x5x3x3x2

= 2250 sq.m

here

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