Question

the perimeter of triangular field is 450 m and its sides are in ratio13:12:5:find area of triangle ​

Answer 1

Step-by-step explanation:

Perimeter, p = 450m

semi-perimeter, s = p/2 = 450/2 = 225

Now, we'll find the sides of the triangle

So, let the ratio be x

(a + b + c = perimeter)

Therefore, 13x + 12x + 5x = 450

30x = 450

x = 450/30 = 15

Therefore,

a = 13x = 13×15 = 195; (s-a)=225-195=30

b = 12x = 12×15 = 180; (s-b)=225-180=45

c = 5x = 5×15 = 75; (s-c)=225-75=150

Now,

Area of triangle =

$\sqrt{s(s - a)( s-b )(s - c)}$

$\sqrt{225 \times 30 \times 45 \times 150}$

$\sqrt{3 \times 3 \times 5 \times 5 \times 2 \times 3 \times 5 \times 3 \times 3 \times 5 \times 2 \times 3 \times 5 \times 5}$

Now, We'll pair up

$\sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5}$

And take common one out from pairs

=> 2 × 3 × 3 × 3 × 5 × 5 × 5

$= {6750m}^{2}$

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Answer 2

Answer:

Step-by-step explanation: