The perimeter of two similar triangle are 25 cm and 15 cm. If one side of the first tringal is 9 cm find the corresponding side of the second triangle.
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Answer:
5.4
Step-by-step explanation:
let the two triangles be
ABC and PQR
AB+BC+CA= 25
PQ+QR+RP= 15
AB =9cm
find PQ?
AB/PQ = BC/QR = CA/RP = k
AB+BC+CA = 25
k(PQ+QR+RP)= 25
k = 25/15
AB/PQ = 25/15
9/PQ =25/15
9*15/25= PQ
5.4 =PQ
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