The perimeter of two similar triangles are 30 cm and 24 cm. If one side of the first triangle is 12 cm, determine
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Let ΔABC ~ ΔDEF
then , AB/DE=BC/EF=AC/DF=AB+BC+AC/DE+EF+DF
=Perimeter of triangle ABC/Perimeter of triangle DEF=AB/DE
=30/24=12/DE
DE=9.6 cm
then , AB/DE=BC/EF=AC/DF=AB+BC+AC/DE+EF+DF
=Perimeter of triangle ABC/Perimeter of triangle DEF=AB/DE
=30/24=12/DE
DE=9.6 cm
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