the perimeter of two square are 40 cm and 32 cm find the perimeter of a third square whose area is equal to the difference of the area of two square
Answers
Answered by
9
We know perimeter of square = 4(side)
So Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third Square = (10*10) - (8*8 )
= 36 cm
So side of third square = 6 [because area of square = side*side]
Perimeter = 4*Side = 4*6 = 24 cm
So Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third Square = (10*10) - (8*8 )
= 36 cm
So side of third square = 6 [because area of square = side*side]
Perimeter = 4*Side = 4*6 = 24 cm
arpan33:
thank you soooooo much
ur most welcome
can you tell me form were the 10*10 has came
as we know that area of a sequre is side*side ...for first it is 10*10
similarly 8*8
as i see 10*10- 8*8 how it becom 36
100-64=36
Similar questions