Math, asked by pinkymahendar999, 1 month ago

the perimeter of two square is 14m and 92m respectively find the perimeter of another square equal in area to the sum of the first two squares.






please help me because tomorrow is my test in school please help me​

Answers

Answered by myogashree93
1

Answer:

Hope it helps u

Step-by-step explanation:

Solution

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It is given that

Perimeter of first square =60 m

Side =60/4=15 m

Perimeter of second square =144 m

Side =144/4=36 m

So the sum of perimeters of two squares 60+144=204 m

Sum of areas of these two squares =15

2

+36

2

=225+1296

=1521 m

2

Here

Area of third square =1521 m

2

We know that

So we get

Side =

Area

=

1521

It can be written as

=

3×3×13×13

=3×13

=39 m

Here

Perimeter =4×side

Substituting the values

4×39

=156 m

Answered by as5123106
1

It is given that

Perimeter of first square =60 m

Side =60/4=15 m

Perimeter of second square =144 m

Side =144/4=36 m

So the sum of perimeters of two squares 60+144=204 m

Sum of areas of these two squares =15

2

+36

2

=225+1296

=1521 m

2

Here

Area of third square =1521 m

2

We know that

So we get

Side =

Area

=

1521

It can be written as

=

3×3×13×13

=3×13

=39 m

Here

Perimeter =4×side

Substituting the values

4×39

=156 m

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