the perimeter of two square is 14m and 92m respectively find the perimeter of another square equal in area to the sum of the first two squares.
please help me because tomorrow is my test in school please help me
Answers
Answer:
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Step-by-step explanation:
Solution
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It is given that
Perimeter of first square =60 m
Side =60/4=15 m
Perimeter of second square =144 m
Side =144/4=36 m
So the sum of perimeters of two squares 60+144=204 m
Sum of areas of these two squares =15
2
+36
2
=225+1296
=1521 m
2
Here
Area of third square =1521 m
2
We know that
So we get
Side =
Area
=
1521
It can be written as
=
3×3×13×13
=3×13
=39 m
Here
Perimeter =4×side
Substituting the values
4×39
=156 m
It is given that
Perimeter of first square =60 m
Side =60/4=15 m
Perimeter of second square =144 m
Side =144/4=36 m
So the sum of perimeters of two squares 60+144=204 m
Sum of areas of these two squares =15
2
+36
2
=225+1296
=1521 m
2
Here
Area of third square =1521 m
2
We know that
So we get
Side =
Area
=
1521
It can be written as
=
3×3×13×13
=3×13
=39 m
Here
Perimeter =4×side
Substituting the values
4×39
=156 m