Question

the perimeter of two squares are 14 and 96 M respectively find the perimeter of another square equal in area to the sum of the first two squares

Answer 1

FIRST OF ALL FIND THE SIDES OF GIVEN SQUARES....
4a=14
a=7/2

its area...I.e..a^2 =49/4=12.25

2ND SQUARE. .
4a=96
a=24m

a^2=576m^2

SUM OF THERE AREAS
576 + 12.25=588.25

AREA OF NEW SQUARE FORMED IS
588.25
IT'S SIDE
a=14x underroot 3
its perimeter=4 x its side

do your answer is
96.32 approx