the perimeter of two squares are 2 and 2.8 M find the perimeter of a square whose area is equal to the sum of areas of these two squares
Answers
Answered by
2
perimeter of a square = 4a
side of 1st square
4a = 2 m
a = 0.5 m
side of 2nd square
4a' = 2.4 m
a' = 0.6 m
area of 2 sqs : 0.5^2 + 0.6^2 = 0.61 m^2
area of new square = a^2
a^2 = 0.61 m^2
a = 0.78 m
4a = 4×0.78 = 3.12 m
side of 1st square
4a = 2 m
a = 0.5 m
side of 2nd square
4a' = 2.4 m
a' = 0.6 m
area of 2 sqs : 0.5^2 + 0.6^2 = 0.61 m^2
area of new square = a^2
a^2 = 0.61 m^2
a = 0.78 m
4a = 4×0.78 = 3.12 m
shreeram9:
but when I was doing someone changed it. But u just change it na while putting
if it is taken as 2.8 ans would be right
i do it
how this 7.8 comes
ques is that area of the new square = sum of areas of 2 squares
ok
sum of areas of 2 squares = .74
a^2 = .74 taking sq root a = .86
when taken as 2.8 it is the ans.
sry 4 confusing u
Answered by
2
❤❤Hey buddy ❤❤
⏬⏬Here is the Answer⏬⏬
⭐⭐3.12 meter⭐⭐
✌✌Hope it's help you✌✌
✔✔ Mark me brainlist ✔✔
⏬⏬Here is the Answer⏬⏬
⭐⭐3.12 meter⭐⭐
✌✌Hope it's help you✌✌
✔✔ Mark me brainlist ✔✔
Similar questions