Question

The perimeter of two squares are 24 cm and 32 cm respectively what is the perimeter of third square whose area is equal to the sum of area of two squares

Answer 1

given two squares have a same perimeter

let, perimeter of first square= 24 cm

now 4× one side = 24

one side = 24/4= 6cm

in second square perimeter= 32cm

4×one side =32

one side = 32/4=8cm


now area of first square = side ×side = 6×6=36cm^2

and second= 8×8= 64cm^2


in question given that ,

third square area = sum of areas of first and second square

so, third area = 36+64= 100 cm^2

now third area = side × side = 100 cm^2

let side = A

so A^2= 100

A= √100= 10 cm

now perimeter= 4× one side = 4×10= 40 cm

perimeter of third square= 40cm

hope it help you

Answer 2

Answer:

40cm

Step-by-step explanation:

Given two squares have a same perimeter

let, perimeter of first square= 24 cm

now 4× one side = 24

one side = 24/4= 6cm

in second square perimeter= 32cm

4×one side =32

one side = 32/4=8cm

now area of first square = side ×side = 6×6=36cm^2

and second= 8×8= 64cm^2

in question given that ,

third square area = sum of areas of first and second square

so, third area = 36+64= 100 cm^2

now third area = side × side = 100 cm^2

let side = A

so A^2= 100

A= √100= 10 cm

now perimeter= 4× one side = 4×10= 40 cm

perimeter of third square= 40cm

hope it helps you