The perimeter of two Squares are 2m and 2.8m. Find the perimeter of a square whose area is equal to the sum of areas of these two Squares
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2 m is equal to 200 cm
2.8 m is equal to 280 cm
Perimeter of square = 4 x side
side of first square = 200/4 = 50 cm
side of second square = 280 /4 = 70 cm
Area of square = 2500 and 4900
sum of area = 2500 + 4900 = 7400
side of area = √7400 = 86.023
perimeter = 4 x 86.023 = 344.092 cm
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9
perimeter of 1 st square = 2 m
Let A is side of square then,
4xA= 2
A= 2/4= 0.5 m
Area of 1st Square= 0.5x0.5= 0.25 sq. m
perimeter of 2nd square= 2.8 m
Let B is side of Square then,
4xB= 2.8
B= 2.8/4= 0.7 m
Area of 2nd Square= BxB= 0.7x0.7= 0.49 Sq.m
Total Area= area of 1st + area of 2nd= 0.25+ 0.49
= 0.74 Sq. M
Let Side of New Square as C
Then, CxC= 0.74 sq. m
C= Sq root of 0.74 =0.86 m
Perimeter= 4x0.86= 3.44 m
Answer is 3.44 m
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