Question

the perimeter of two squares are 40 and 96 respectively find the perimeter of another squares in the area to the sum of the first two square.​

Answer 1

Step-by-step explanation:

Given, Perimeter of one square = 40 m

Suppose the length of square = a

1

So, 4a

1

= 40 m Side (a

1

) = 40 ÷ 4 = 10 m

Area of a square = a

1

×a

1

=10×10=100m

2

Perimeter of second square = 96 m

Suppose the length of square = a

2

So, 4a

2

= 96 m Side (a

2

) = 96 × 4 = 24 m

Area of a square = a

2

×a

2

=24×24=576m

2

As we know, perimeter of another square is equal in area to the sum of the first two square.

So, area of another square = 100 + 576 = 676 m

Area of a square = a

3×a3

676 = (a

3 ) 2ora 3 =26

Thus, perimeter = 4a

3

=4×26=104m