the perimeter of two squares are 40 m and 96 m .find the perimeter of another squares equal in area to the sum of the first two squares
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4a=40
a=10
4b=96
b=24
a^2+b^2=c^2
10^2+24^2=c^2
√676=c
c=26
therefore perimeter=26×4=104
a=10
4b=96
b=24
a^2+b^2=c^2
10^2+24^2=c^2
√676=c
c=26
therefore perimeter=26×4=104
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