The perimeter of two squares are 40cm & 32cm. Find the perimeter of a third square whose area is equal to the difference of the area of the two square?
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let the side of first square be x
4x=40
x=10
let the side of Second square be y
4y=32
y=8
let the side of the third square be z
now according to question
z²=x²-y²
z²=100-64
z²=36
z=6
perimeter of third square =4z=4*6=24cm
4x=40
x=10
let the side of Second square be y
4y=32
y=8
let the side of the third square be z
now according to question
z²=x²-y²
z²=100-64
z²=36
z=6
perimeter of third square =4z=4*6=24cm
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