Question

the perimeter of two squares are 40m and 96m . find the perimeter of another square equal in area to the sum of the first two squares

Answer 1

Side of square1 is= 40/4=10m
Side of square2 is=96/4=24m
Area of another square=(S1)^2+(S2)^2
=(10)^2+(24)^2
=100+576
=676m
Side of another square=
$\sqrt{676}$
=26m
Perimeter of another square=26×4
=104m

Answer 2

$\bf \large \it{Hey \: User!!!}$

perimeter of the 1st square = 40m
therefore side × 4 = 50m
>> side = 40/4
>> side = 10m

hence, the side of the 1st square is 10m.

perimeter of the second square = 96m
therefore 4 × side = 96m
>> side = 96/4
>> side = 24m

the side of the second square is 24m.

according to the question, the area of the new square is equal to the area of the sum of 1st and second square.

therefore area of the new square = (24)² + (10)²
= 576 + 100
= 676m²

>> side × side = 676m²
>> side² = 676m²
>> side = √676
>> side = 26m

the side of the new square is 26m.

hence, it's perimeter = 26 × 4 = 104m

$\bf \large \it{Cheers!!!}$