Question

the perimeter of two squares are 52m and 326m.find the length of the side of the square whose area is equal to the sum of the areas of the two squares.​

Answer 1

Answer:

Square 1=52m(perimeter)

Therefore ...side=52/4=13cm

Area=side×side=13×13=169

Square 2=326m(perimeter)

Therefore side=81.5cm

Area=side×side=81.5×81.5=66,422.5

Now...area of bigger square=66,422.5+169

=66,591.5

Side of bigger square=(66,591.5)^1/2

=258 m

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Answer 2

Step-by-step explanation:

Given:-

the perimeter of two squares are 52m and 326m.

To find:-

Find the length of the side of the square whose area is equal to the sum of the areas of the two squares.

Solution:-

Perimeter of the first square(P1)=52m

Perimeter of the second square(P2)=326m

We know that perimeter of the square=4×side units

=>Side of the square =Perimeter/4 units

=>Side of the first square=52/4=13 m

Area of the square =side×side sq.units

=>Area of the first square

=>A1=13×13

=>A1=169 sq.m------(1)

Side of the second square=326/4

=>81.5 m

Area of the second square

(A2)=81.5×81.5

=>A2=6642.25 sq.m------(2)

According to the given problem,

area is equal to the sum of the areas of the two squares.

A=A1+A2

=>A=169+6642.25

=>A=6811.25 sq.m

Now side of the new square

= >√6811.25

=>82.53 m(approximately)

Answer:-

Side of the new square=82.53 m