Math, asked by RonakJain21, 1 year ago

the perimeter of two squares are 60 M and 144 M respectively find the perimeter of another square equal in area to the sum of the first 2 square

Answers

Answered by tejasri2
12
Perimeter of first square = 60

4s = 60

s = 60/4 = 15

Its area = S² = 15×15 = 225 sq . cm


Perimeter of second square = 144

4s = 144

s = 144/4

s = 36

Area = S2 = 36×36

=1,296


Area of new square = 225+1296

= 1,521

S² = 1521

S = 39

Perimeter = 4S

= 4(39)

= 156 cm



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Answered by harshu44
4
Hello Dear!!!

Here's your answer...

Given that,

Perimeter of two squares is 60 and 144

First square perimeter is 60

Perimeter of square is 4s

4s = 60

s = 60/4

s = 15

then area is

(15)^2

225

Second square perimeter is 144

4s = 144

s = 144/4

s = 36

then area is

(36)^2

1296

Sum of areas of these two squares is

225+1296

1521

Perimeter of this square is

(s)^2 = 1521

s = √1521

s = 39

Perimeter is.

4s

4(39)

156

____________________________



Hope this helps you....
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