the perimeter of two squares are 60 M and 144 M respectively find the perimeter of another square equal in area to the sum of the first 2 square
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Perimeter of first square = 60
4s = 60
s = 60/4 = 15
Its area = S² = 15×15 = 225 sq . cm
Perimeter of second square = 144
4s = 144
s = 144/4
s = 36
Area = S2 = 36×36
=1,296
Area of new square = 225+1296
= 1,521
S² = 1521
S = 39
Perimeter = 4S
= 4(39)
= 156 cm
Hope it helps u : )
4s = 60
s = 60/4 = 15
Its area = S² = 15×15 = 225 sq . cm
Perimeter of second square = 144
4s = 144
s = 144/4
s = 36
Area = S2 = 36×36
=1,296
Area of new square = 225+1296
= 1,521
S² = 1521
S = 39
Perimeter = 4S
= 4(39)
= 156 cm
Hope it helps u : )
RonakJain21:
thank you very much
Answered by
4
Hello Dear!!!
Here's your answer...
Given that,
Perimeter of two squares is 60 and 144
First square perimeter is 60
Perimeter of square is 4s
4s = 60
s = 60/4
s = 15
then area is
(15)^2
225
Second square perimeter is 144
4s = 144
s = 144/4
s = 36
then area is
(36)^2
1296
Sum of areas of these two squares is
225+1296
1521
Perimeter of this square is
(s)^2 = 1521
s = √1521
s = 39
Perimeter is.
4s
4(39)
156
____________________________
Hope this helps you....
Here's your answer...
Given that,
Perimeter of two squares is 60 and 144
First square perimeter is 60
Perimeter of square is 4s
4s = 60
s = 60/4
s = 15
then area is
(15)^2
225
Second square perimeter is 144
4s = 144
s = 144/4
s = 36
then area is
(36)^2
1296
Sum of areas of these two squares is
225+1296
1521
Perimeter of this square is
(s)^2 = 1521
s = √1521
s = 39
Perimeter is.
4s
4(39)
156
____________________________
Hope this helps you....
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