the perimeter of two squares are 60 meters and 144 meters respectively. find the perimeter of another square equal in area to the sum of the first two squares.
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For the first square:
Perimeter=4×side
or, 4×side=60m
or, side=60/4=15m
So, area = (side)^2=225m
For the second square:
Perimeter=4×side
or, side=perimeter/4=144/4=36m
So, area=(36)^2=1296m
Area of the square whose are is equal to the area of the two given square=1296+225=1521m
Its side = √1521=39m
So perimeter = 4×39=156m
Perimeter=4×side
or, 4×side=60m
or, side=60/4=15m
So, area = (side)^2=225m
For the second square:
Perimeter=4×side
or, side=perimeter/4=144/4=36m
So, area=(36)^2=1296m
Area of the square whose are is equal to the area of the two given square=1296+225=1521m
Its side = √1521=39m
So perimeter = 4×39=156m
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