the perimeter of two squares are 6744 respectively find the perimeter of another square equal in area to the sum of first two square
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perimeter of A=44
4a=44
a=11
area of A=a^2=11^2=121
perimeter of B=67
4a=67
a=16.7
area of B=a^2=16.7^2=278.89
Area of A+B(say C)=121+278.89
=399.89
area of C=> a^2=399.89
a=√399.89
a=19.9
Therefore, perimeter of C=4a
=4(19.9)
=79.6
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