Question

the perimeter of two squares are in the ratio 8:15 , find the ratio between the lengths of their sides .​

Answer 1

Answer:

Step-by-step explanation:

Let the perimeter of first square = 8x

∴ Side of the first square = Perimeter/4 = 8x/4

and the perimeter of second square = 7x

∴ Side of the second square = Perimeter/4

= 15x/4

Now, the ratio between the sides of the square

= 8x/4 : 15x/4

= 8 : 15

Answer 2

Given:

• Perimeter of two squares are in the ratio 8:15

To Find:

• Ratio between the lengths of sides of given squares

Solution:

Let the side of first square be 'a' and side of second square be 'b'

We know that,

↬ Perimeter of Square= 4×(Length of side)

Now,

Perimeter of first square= 4a

Perimeter of second square= 4b

Also,

$\longrightarrow\sf{\dfrac{Perimeter\:of\:first\:square}{Perimeter\:of\:second\:square}=\dfrac{8}{15}}$

$\longrightarrow\sf{\dfrac{\cancel{4}a}{\cancel{4}b}=\dfrac{8}{15}}$

$\longrightarrow\sf\pink{\dfrac{a}{b}=\dfrac{8}{15}}$

Hence, the ratio between the lengths of their sides is $\sf{\dfrac{8}{15}}$.

Some Imporatant Formulae

➳ Area of Square= (Side)²

➳ Perimeter of Rectangle= 2(l+b)

➳ Area of Rectangle= Length×Breadth