Question

The perimeter of two squares are40 cm and 32 cm .find the perimeterof 3rd square whose area is equal to the difference of the are of the area of squares​

Answer 1

Answer:

24 cm

Step-by-step explanation:

Perimeter of first square = 40 cm

Side of first square = 40/4 cm = 10 cm

Perimeter of second square = 32 cm

Side of second square = 32/4 cm = 8 cm

Area of first square = $(10 cm)^{2}$ = 100 $cm^2$

Area of second square = $(8 cm)^2$ = 64 $cm^{2}$

Difference = (100 - 64) $cm^2$ = 36 $cm^2$

Side of third square = $\sqrt{36}$ cm = 6 cm

Perimeter of third square = 4 x 6 cm = 24 cm