Question

the perimeter of two squares is equal to 428cm and 396cm. Find the area of square whose area is equal to the area of two squares.​

Answer 1

Step-by-step explanation:

Given, Perimeter of one square = 40 m

Suppose the length of square = a

1

So, 4a

1

= 40 m Side (a

1

) = 40 ÷ 4 = 10 m

Area of a square = a

1

×a

1

=10×10=100m

2

Perimeter of second square = 96 m

Suppose the length of square = a

2

So, 4a

2

= 96 m Side (a

2

) = 96 × 4 = 24 m

Area of a square = a

2

×a

2

=24×24=576m

2

As we know, perimeter of another square is equal in area to the sum of the first two square.

So, area of another square = 100 + 576 = 676 m

Area of a square = a

3

×a

3

676 = (a

3

)

2

ora

3

=26

Thus, perimeter = 4a

3

=4×26=104m

104 m answer

Answer 2

.

GIVEN,

PERIMETER OF TWO SQUARES = 428cm AND 396cm

TO FIND:

AREA OF SQUARE

SOLUTION:

1) PERIMETER OF SQUARE = 4 × SIDE

428 = 4 × SIDE

.

= 107

2) PERIMETER OF SQUARE = 4 × SIDE

396 = 4 × SIDE

.

= 99

1) AREA OF SQUARE = SIDE²

= 107²

= 11449cm²

2) AREA OF SQUARE = SIDE²

= 99²

= 9801cm²

$\sf \red{THUS, AREA OF SQUARE ARE} \\ \sf \red{11449CM² \: AND \: 9801CM²}$