Question

the perimeter of two triangles are 25 and 15 cm respectively. If one side of the triangle is 9 cm,find the length of the corresponding side of the second triangle.​

Answer 1

*Question:-

• The perimeter of two *similar triangles are 25 cm and 15 cm respectively. If one side of the triangle is 9 cm, find the length of the corresponding side of the second triangle.

★ GivEn:-

• The perimeter of two similar triangles are 25 cm and 15 cm
• One side of a triangle is 9 cm

★ To Find:-

• The length of corresponding side of another triangle

★ Solution:-

We know that,

In two similar triangles, the perimeters of the triangles would be in the ratio of their corresponding sides.

Therefore,

The ratio of their perimeters is

$\sf \dfrac{ \triangle \: 1}{ \triangle \: 2} = \dfrac{25}{15}$

And the corresponding sides of the triangles would be in the same ratio.

$\sf \implies \dfrac{9}{ side \: of \: \triangle \: 2} = \dfrac{25}{15}$

$\sf \implies side \: of \: \triangle \: 2 = \dfrac{15 \times 9}{25}$

$\sf \implies side \: of \: \triangle \: 2 = \dfrac{135}{25}$

$\sf \implies side \: of \: \triangle \: 2 = 5.4 \: cm$

Answer 2

Answer:

*Question:-

The perimeter of two *similar triangles are 25 cm and 15 cm respectively. If one side of the triangle is 9 cm, find the length of the corresponding side of the second triangle.

★ GivEn:-

The perimeter of two similar triangles are 25 cm and 15 cm

One side of a triangle is 9 cm

★ To Find:-

The length of corresponding side of another triangle

★ Solution:-

We know that,

In two similar triangles, the perimeters of the triangles would be in the ratio of their corresponding sides.

Therefore,

The ratio of their perimeters is

\sf \dfrac{ \triangle \: 1}{ \triangle \: 2} = \dfrac{25}{15}

△2

△1

=

15

25

And the corresponding sides of the triangles would be in the same ratio.

\sf \implies \dfrac{9}{ side \: of \: \triangle \: 2} = \dfrac{25}{15}⟹

sideof△2

9

=

15

25

\sf \implies side \: of \: \triangle \: 2 = \dfrac{15 \times 9}{25}⟹sideof△2=

25

15×9

\sf \implies side \: of \: \triangle \: 2 = \dfrac{135}{25}⟹sideof△2=

25

135

\sf \implies side \: of \: \triangle \: 2 = 5.4 \: cm⟹sideof△2=5.4cm