the perimeter of35m wide recetegular field is 190 m find Its
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perimeter of rectangle=2(l+b)
190m=2(l+35)
190/2=l+35
95=l+35
l=95-35
=60m
190m=2(l+35)
190/2=l+35
95=l+35
l=95-35
=60m
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