the perimeter ofa square and the circumference of a circle are equal.If the length of each side of the square is 22 cm ,find: (1) perimeter of the square (2) circumference of the circle (3) radius of
solution =
1 part . 4×side
22×4=88
2 part=88
3 part =
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solution =
1 part. 4xside
22*4=88
2 part=88
3 part =
88 = 2x22 xr
88 = 44 7 xr
r = 88 x 7 : 44
r = 2 x 7
r = 14cm
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