Question

the perimeter s of two similar triangles is 25cm and 15cm respectively. if one side of the first triangle is 9cm then find the side of second triangle​

Answer 1

Answer:

Step-by-step explanation:

Given :-

Perimeter of 1st Triangle = 25 cm

Perimeter of 2nd Triangle = 15 cm

One side of Triangle = 9 cm

To Find :-

Side of 2nd triangle = ??

Formula to be used :-

Ratio of corresponding sides of similar triangles is same as the ratio of their perimeters.

AB/PQ = BC/QR = AC/PR

Solution :-

Let the two triangles be ABC and PQR.

AB/PQ = BC/QR = AC/PR = 25/15

⇒ 9/PQ = 25/15

⇒ 25 PQ = 15 × 9

⇒ PQ = (15 × 9)/25

⇒ PQ =(3 × 9 )/5

⇒ PQ = 27/5

⇒ PQ = 5.4 cm

Hence, the side of second triangle​ 5.4 cm.

Answer 2

Step-by-step explanation:

$\bf \huge \: Question \: \:$

• The perimeter s of two similar triangles is 25cm and 15cm respectively. if one side of the first triangle is 9cm then find the side of second triangle

___________________________

$\bf \huge \: Given \: \:$

• the perimeter s of two similar triangles is 25cm and 15cm respectively.
• one side of the first triangle is 9cm

___________________________

$\bf \huge \:To\: Find \:$

• the side of second triangle

_____________________________

In similar trione side of the angles, the perimeter of the triangles will be in the ratio of their corresponding sides.

Now, per(∆ABC)/per(∆DEF)=AB/DE

We ge

25/15=9/D

25DE =9×15

DE=135/25

DE=5.4