Question

the perimeterof a triangle is 49 one side is 7cn longer than another side and 5 cm shorter than third side

Answer 1

let the side be x cm.
2nd side is x-7 cm.
3rd side is x+5 cm.
perimeter is 49..
so x + x-7 +x +5 = 49.
so 3x = 51.
x = 17.

17, 22, 10 are the sides

Answer 2

let the third side be x
one side is x-7
another side is x+5
we know that perimeter of triangle is 49cm.
x+x-7+x+5=49
3x-2=49
3x=49+2
x=51/3
x=17
one side is 17cm
second side is x-7=17-7=10
third side is x+5=17+5=22