Question

The perimeters of a rhombus and a square are equal to 52 cm. If one of the
diagonals of the rhombus is 10 cm, find the difference in their areas.




please answer me ​

Answer 1

Answer:

first find side of square =52/4=13

Now find area of square =13*13=169

then 169 is equal the area of rhombus

169=10*X

X=169/10=16.9