Question

The perimeters of a square and a regular hexagon are equal .Find the ratio of the hexagon to the area of the square. ​

Answer 1

Answer:

Step-by-step explanation:

let the side of square be x

let the side of hexagon be y

A.T.Q:4x=6y

x=3/2*y

area of square=x^2

                       =9*y^2/4

area of hexagon=3root3/2*y^2

therefore ratio of area of hexagon to area of square=2:root3

Answer 2

Answer:

2√3 : 3

Step-by-step explanation:

Let,

Side of square = x units.

Side of regular hexagons = y units.

Therefore,

4x = 6

Now,

Area of sq. = y/4 × y^2

and

Area of hexagon = (3√3)/2 y^2

So,

Required ratio = (3√3)/2 y^2 × y/4(y)^2 = 2√3 : 3

Thus, the required ratio is 2√3 : 3