Question

the perimeters of a square field and a rectangular field are the same. If one side of the rectangular field is 18m and one side of the square field is 15m,find:
(i) the area of the rectangular field and
(ii) the total area of both the field
wrong answer will be banned and right will get 100 b point​

Answer 1

Answer:

Step-by-step explanation:

Given data,

The perimeters of a square field and a rectangular field are the same.

If one side of the rectangular field is $18m$ and one side of the square field is $15m$.

We know that

Perimeter of the square $=4\times$ Side

$=4\times15=60m$

By the given data, perimeters of the square and the rectangular field are same

So,

Perimeter of the rectangle $=60m$

$\Rightarrow 2(l+b)=60m$

$\Rightarrow 2(18+b)=60$

$\Rightarrow 18+b=30$

$\Rightarrow b=12m$.

Therefore, the other side of the rectangle $=12m$

(i) Area of the rectangle $=l\times b=18\times12=216m^{2}$

Area of the square $=side^{2}=15\times15=225m^{2}$

(ii) The total area of both the field $=225+216=441m^{2}$.

Answer 2

Given,

The perimeter of a square and rectangular is same

$4a=2(l+b)$

One side of rectangle is $18cm$

One side of square is $15cm$

$4a=2(l+b)$

$4\times15=2(18+b)$

$30=18+b$

$b=12$

(i) Area of rectangle $=l\times b$

$l=18,b=12$

$A=18\times 12$

$A=216$ square meter

(ii)Area of square $=a^{2}$

$A=15\times 15$

$A=225$ square meter

Total area $=$ Area of rectangle $+$Area of square

$A=216+225=441$ square meter.

Therefore, the total area is $441$ square meter.