Question

The perimeters of two similar triangles ABC and PQR are respectively 36cm and 24cm.If PQ=10cm.Find AB.

Answer 1

SOLUTION

We know that the Ratio of corresponding sides of similar ∆ is same as the ratio of their perimeters.

Therefore, we have

=) ∆ABC~ ∆PQR

$= > \frac{</strong><strong>AB</strong><strong>}{</strong><strong>PQ</strong><strong>} = \frac{</strong><strong>B</strong><strong>C}{</strong><strong>QR</strong><strong>} = \frac{</strong><strong>AC</strong><strong>}{</strong><strong>PR</strong><strong>} = \frac{36}{24} \\ \\ = > \frac{</strong><strong>AB</strong><strong>}{</strong><strong>PQ</strong><strong>} = \frac{36}{24} \\ \\ = > \frac{</strong><strong>AB</strong><strong>}{10} = \frac{36}{24} \\ = > </strong><strong>AB</strong><strong> = 15cm$

hope it helps ☺️

Answer 2

Answer:

Given :

Perimeter of ΔABC = 36 cm

Perimeter of ΔPQR = 24 cm

and PQ = 10 cm

To find : AB = ?

Since,

ΔABC ~ ΔPQR

Perimeter of ΔABC/Perimeter of ΔPQR = AB/PQ

=> 36/24 = AB/10

=> 3/2 = AB/10

=> AB = (3/2)*10

=> AB = 15 cm

Hence, the value of AB is 15 cm ,,