The perimeters of two similar triangles ABC and PQR are respectively 40 cm and 60 cm. If PQ = 12 cm then find
ar(PQR)/ar (ABC)
02:3
03:7
09:4
04:9
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PQ = 12
then
Ab= 12
therefore they are similar
then all sides are 12
given
perimeter is 40 and 60
area of pqr = 1/ 2 ( a + b )
= 1/2( 12+12)
=1/2× 24
= 12
so,
Answered by
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Answer:
(D)4:9 I think this is right answer
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