the perimeters of two similar triangles are 25 centimetre and 20 CM respectively if one side of the first angle is 12 CM determine the corresponding side of the second triangle
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Step-by-step explanation:
Let △ABC and △DEF be two similar triangles of perimeters P1 and P2 respectively.
Also, let AB=12 cm, P1=30 cm and P2=20 cm.
Then,
DEAB=EFBC=DFAC=P2P1 [∵ Ration of corresponding sides of similar triangles is equal to the ratio of their perimeters]
⇒ DEAB=P2P1
⇒ DE12=2030
⇒ DE=3012×20cm=8cm
Hence, the corresponding side of the second triangle is 8 cm
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