The perimeters of two similar triangles are 25 cm and 16 cm respectively. If the
side of first triangle is 9 cm, then find the side of other triangle
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HY DUDE ...HERE IZ UA ANSWER....
Assume ABC and PQR to be triangles
we have ,
∆ ABC congruent to ∆ PQR
Perimeter of ∆ ABC =25cm
Perimeter of ∆PQR =16cm
AB=9cm
PQ=?
SINCE.....∆ABC CONGRUENT TO ∆PQR
Then the ratio of the perimeter of the ∆ = ratio of the corresponding sides
25/12=AB/PQ
25/16=9/PQ
PQ=16*9/25
=28.8Cm.........
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