the perimeters of two similar triangles are 30centimetre and 20 CM respectively if one side of the first angle is 12 CM determine the corresponding side of the second triangle
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Answered by
0
Answer:
Let △ABC and △DEF be two similar triangles of perimeters P
1
and P
2
respectively.
Also, let AB=12 cm, P
1
=30 cm and P
2
=20 cm.
Then,
DE
AB
=
EF
BC
=
DF
AC
=
P
2
P
1
[∵ Ration of corresponding sides of similar triangles is equal to the ratio of their perimeters]
⇒
DE
AB
=
P
2
P
1
⇒
DE
12
=
20
30
⇒ DE=
30
12×20
cm=8cm
Hence, the corresponding side of the second triangle is 8 cm
Answered by
0
Answer:
your answer is 12 cm determine
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