Question

The perimeters of two similar triangles are 40 cm an 35 cm respectively. If one side of the first triangle is 16 cm. Then the corresponding side of the second triangle is

Answer 1

$perimeter = a + b + c \div 2$

$perimeter = 40 + 35 + 16 \div 2$

$perimeter = 91 \div 2$

$perimeter = 41.5$

$by \: herons \: formula$

$\sqrt{(s - a)(s - b)(s - c)}$

$\sqrt{(41.5 - 40)(41.5 - 35)(41.5 - 16)}$

$(41.5 \times 10 - 40)(41.5 \times 10 - 35)(41.5 - \times 10 - 16)$