Question

the perimeters of two squares are 428 cm and 396 cm find the area of a square whose area is equal to the sum of area of two squares ​

Answer 1

Answer:

= 21,250cm²

Explanation:

Let two squares are S1 and S2

Perimeter of S1 = 428 cm

Perimeter of S1 = 4 × S1

4× S1 = 428 cm

S1 = 428/4

S1 = 107 cm

Area of S1 = S1² or S1 × S1

Area of S1 = 107 × 107 = 11,449 cm²

Perimeter of S2 = 396 cm

Perimeter of S2 = 4 × S2

4 × S2 = 396

S2 = 396/4

S2 = 99 cm

Area of S2 = S2 × S2

Area of S2 = 99 × 99 = 9,801 cm²

The area of a square whose area is equal to the sum of area of two squares is :

Area of new square = Area of S1 + Area of S2

Area of new square = 11,449 + 9,801 = 21,250 cm²

Answer 2

Answer:

this is a answer of this question ⬇️

Explanation:

the perimeters of two squares are 428 cm and 396 cm find the area of a square whose area is equal to the sum of area of two squares