Question

The perimeters of two squares are 60 metres and 140 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.​

Answer 1

Answer:

It is given that

Perimeter of first square =60 m

Side =60/4=15 m

Perimeter of second square =144 m

Side =144/4=36 m

So the sum of perimeters of two squares 60+144=204 m

Sum of areas of these two squares =15

2

+36

2

=225+1296

=1521 m

2

Here

Area of third square =1521 m

2

We know that

So we get

Side =

Area

=

1521

It can be written as

=

3×3×13×13

=3×13

=39 m

Here

Perimeter =4×side

Substituting the values

4×39

=156 m