Question

The perimeters of two squares are 60 metres and 144 metres respectively. Find the
perimeter of another square equal in area to the sum of the first two squares.​

Answer 1

Answer:

51

Step-by-step explanation:

the first square perimeter is=60÷4=15

the second square perimeter=144÷4=36

so, the last square perimeter=36+15=51

Answer 2

Answer:

Step-by-step explanation:

ok so lets go

perimeter of square = 4a (where a is the side measure of the square)

perimeter of first square = 4 x a₁ = 60 ( let a₁ be the side length of first square)

⇒a₁ = 60/4

⇒a₁=15 metre

area of first square with side 15 m = 15 x 15 ⇒225 m²

perimeter of second square = 4 x a₂ = 144

⇒a₂ = 144/4

⇒a₂ = 36 metre

area of second square with side 36 m = 36 x 36 ⇒ 1296 m²

Area of Third square = area of first square + area of second square

⇒225 +1296 = 1521

area = side²= 1521

side = √1521

side = 39 m

SO perimeter of the third square = 4 x 39

⇒156cm.

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