Question

The perimeters of two squares are 80 cm and 64 cm. Find the perimeter of a
third square whose area is equal to the difference of the areas of the two
squares.

Answer 1

Step-by-step explanation:

We know perimeter of square = 4(side)

So Side of first square = 80/4 = 20 cm

Side of second square = 64/4 = 16 cm

Area of third Square = 20×20 - 16×16

= 144cm

So side of third square = 12 [because area of square = side*side]

Perimeter = 4*Side = 4*12= 48 cm

Answer 2

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GIVEN -

▪︎Perimeter of first square = 80 cm

▪︎Perimeter of first square = 4 × side = 80

= side = 80/4

= side = 20cm

▪︎Perimeter of second square = 64cm

▪︎Perimeter of second square =4 ×side = 64

= side = 64/4

= side = 16cm

SOLUTION -

☆According to the question,

• Difference of the area of the both the squares = area of third square.

Therefore,

▪︎(20)² - (16)² = Area of third square

▪︎400 - 256 = (a)²

▪︎144 = (a)²

▪︎12 = a

Thus,

▪︎Perimeter of third square = 4 × side

▪︎Perimeter of third square = 4 × 12

▪︎Perimeter of third square = 48cm.