Question

The perimeters of two squares are 80cm and 64cm . Find the perimetet of the squars whose area is equal to the difference of the areas of the two squares

Answer 1

Answer:

48

Step-by-step explanation:

first square side = 80/4= 20

Second square side = 64/4=16

first square area = 20*20= 400

second square area = 16*16= 256

areas difference = 400=256= 144

then side of given square = 12

Perimeter = 4* 12= 48