Question

The perimeters of two squares are 848 cm and 436 cm. Find the perimeter of a square
whose area is equal to the sum of the areas of two squares,​

Answer 1

Answer:

each side of first one is 848/4 or 212 cm

each side of the 2nd is 436/4 or 109 cm

so the area of the first = 212^2 cm^2 = 44944 cm^2

the area of the 2nd is 109^2 cm = 11881 cm^2

total area = 56825 cm^2

each side is √56825 = 5√2273

and the perimeter = 20√2273

= appr 953.52

Answer 2

Step-by-step explanation:

perimeter = 4s

4s=848

s=212

area =s*s

=44944

similarly area of other square is

109*109=11881

area of third square=44944+11881=56825

side*side = 56825

so,side = 238.37

perimeter = 238.37*4 =953.51