Question

The perimeters of two squares numbers
60m, 144m, respectively. Find the perimeter
of anather square whose area
is sum of first two squares?

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Answer 1

Perimeter of a square(P) = 4a

Where a=side of the square

P=4a

(They have given that P is 60m)

60=4a

=>a=15m

Area of square is a^2

So are area of first square is 15^2 which is equal to 225m^2


Perimeter of second square (p) = 4a

p=4a

(Where p is given as 144)

=>144=4a

=>a=36m

Area of square is a^2

=>36^2

=>1196m^2

Area of third square is P+p

=>225+1196

=>1421 m^2