Question

the perimetre of an isosceles triangle measures 2 cm more than its height , and the base of the triangle measures 12 cm. find the area of the triangle...

Answer 1

area of triangle ABC=1/2×12×h=6h cm²
or 
perimeter of the triangle= 2+h
 2+h=x+x+12
 2+h=2x+12
 h=2x+10
BC=12 cm
BD= 6 cm ( since isocleles triangle  the altitude on the base is also the median of the triangle )

in triangle ADB,
x= $\sqrt{H^{2} +6^{2}$

AREA OF TRIANGLE ABC=1/2×BASE×HEIGHT+1/2×12×$\sqrt{H^{2} +6^{2}$

area of triangle = 6$\sqrt{H^{2} +6^{2}$cm²