Math, asked by chaman4070lal, 10 months ago

The perimetre of an isoscles triangle is 30metre. The ratio of equal side to its base is 3:2. Find the arm (side) ofthe triangle.​

Answers

Answered by sonabrainly
1

Answer:

Step-by-step explanation:

a similar question which is related to yours

the perimeter of isosceles triangle = 32cm

p of isosceles triangle = 2 * equal side + base

let length of equal side be 3x and base be 2x

then

2 * 3x + 2x = 32 cm

6x + 2x = 32cm

8x = 32 cm

x= 4 cm

length of equal side = 3*4= 12cm

length of base = 2*4=8cm

area of isosceles triangle=b*1/4*√4a2-b2

= 8*1/4√4*144-64

=2√512

=2*22.62

= 45.25cm2

Answered by FIREBIRD
19

Step-by-step explanation:

Lets the side be x

perimeter = side + side + side

30 m = 3x + 3x + 2x

8x = 30

x = 15/4 m

x = 3.75m

so equal sides = 3 × 3.75 = 11.25 m

base = 2 × 3.75 = 7.5 m

#answerwithquality #BAL

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